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Questions
Prove that the rhombus, inscribed in a circle, is a square.
Prove that the cyclic rhombus is a square.
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Solution
Let ABCD be a rhombus, inscribed in a circle
Now, ∠BAD + ∠BCD
(Opposite angles of a parallelogram are equal)
And ∠BAD + ∠BCD =180°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
∴ ∠BAD + ∠BCD = `(180^circ)/2` = 90°
The other two angles are 90°, and all the sides are equal.
∴ ABCD is a square.
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In the given figure, ∠BAD = 65°, ∠ABD = 70°, ∠BDC = 45°
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