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Question
In the given figure, prove that: ∆ ABD ≅ ∆ ACD
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Solution
Proof:
In Δ ABD and Δ ACD,
AD = AD ..............(common)
AB = AC ...............(given)
BD = DC ...............(given)
∴ Δ ABD ≅ Δ ACD .............(S.S.S. Axiom)
Hence proved.
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