Advertisements
Advertisements
प्रश्न
In the given figure, prove that: ∆ ABD ≅ ∆ ACD
Advertisements
उत्तर
Proof:
In Δ ABD and Δ ACD,
AD = AD ..............(common)
AB = AC ...............(given)
BD = DC ...............(given)
∴ Δ ABD ≅ Δ ACD .............(S.S.S. Axiom)
Hence proved.
APPEARS IN
संबंधित प्रश्न
ΔPQR and ΔABC is not congruent to ΔRPQ, then which of the following is not true:
In ΔPQR ≅ ΔEFD then ED =
In the pair of triangles in the following figure, parts bearing identical marks are congruent. State the test and the correspondence of vertices by the triangle in pairs is congruent.
Prove that:
- ∆ ABD ≅ ∆ ACD
- ∠B = ∠C
- ∠ADB = ∠ADC
- ∠ADB = 90°
Which of the following pairs of triangles are congruent? Give reasons
ΔABC;(AB = 8cm,BC = 6cm,∠B = 100°);
ΔPQR;(PQ = 8cm,RP = 5cm,∠Q = 100°).
AD and BE are altitudes of an isosceles triangle ABC with AC = BC. Prove that AE = BD.
In ΔABC, X and Y are two points on AB and AC such that AX = AY. If AB = AC, prove that CX = BY.
It is given that ∆ABC ≅ ∆RPQ. Is it true to say that BC = QR? Why?
Without drawing the triangles write all six pairs of equal measures in the following pairs of congruent triangles.
∆ABC ≅ ∆LMN
Without drawing the triangles write all six pairs of equal measures in the following pairs of congruent triangles.
∆XYZ ≅ ∆MLN
