English

In the given figure, OA = 5, OB = 6, OC = 3 and OD = 10, then ______.

Advertisements
Advertisements

Question

In the given figure, OA = 5, OB = 6, OC = 3 and OD = 10, then ______.

The image displays a quadrilateral ABCD with intersecting diagonal line segments AC and BD meeting at a central point O. It outlines multiple adjacent and intersecting triangles sharing vertex O for geometric property analysis.

Options

  • △ AOB ∼ △ AOD

  • △ AOB ∼ △ BOC

  • △ BOC ∼ △ COD

  • △ AOD ∼ △ COB

MCQ
Advertisements

Solution

In the given figure, OA = 5, OB = 6, OC = 3 and OD = 10, then △ AOD ∼ △ COB.

Explanation:

Given,

OA = 5, OB = 6, OC = 3 and OD = 10.

⇒ `(OA)/(OC) = 5/3`

⇒ `(OD)/(OB) = 10/6 = 5/3`

∴ `(OA)/(OC) = (OD)/(OB)`

From figure,

∠AOD = ∠BOC (Vertically opposite angles are equal)

∴ △ AOD ∼ △ COB (By S.A.S. axiom)

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Similarity (With Applications to Maps and Models) - EXERCISE 15 (A) [Page 214]

APPEARS IN

Selina Concise Mathematics [English] Class 10 ICSE
Chapter 15 Similarity (With Applications to Maps and Models)
EXERCISE 15 (A) | Q 1. (c) | Page 214
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×