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Question
In the given figure, O is the centre of the circle and chord AB : chord CD = 3 : 5. If angle AOB = 60°, angle COD is equal to:
Options
60°
120°
90°
100°
MCQ
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Solution
100°
Explanation:
Given,
Chord AB : Chord CD = 3 : 5
∴ ∠AOB : ∠COD = 3 : 5
⇒ 60° : ∠COD = 3 : 5
⇒ `(60°)/(∠COD) = 3/5`
⇒ ∠COD = `(60° × 5)/3 = (300°)/3` = 100°
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