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In the given figure, D is mid-point of side BC, the area of triangle BEA is equal to area of triangle:

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Question

In the given figure, D is mid-point of side BC, the area of triangle BEA is equal to area of triangle:

Options

  • BED

  • CED

  • CEA

  • ACD

MCQ
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Solution

ACD

Explanation:

  • Since D is the mid-point of side BC, the line segment AD is a median of ΔABC. A median divides a triangle into two triangles of equal area, meaning:
    area of ΔABD = area of ΔACD
  • Similarly, in ΔEBC, D is the mid-point of BC, so ED is a median, which means:
    area of ΔEBD = area of ΔECD
  • Subtracting the area of ΔEBD from the area of ΔABD:
    area of ΔBEA = area of ΔABD − area of ΔEBD
  • Substituting ΔECD$ in place of ΔEBD (since their areas are equal):
    area of ΔBEA = area of ΔABD − area of ΔECD = area of ΔACD

Thus, the area of triangle BEA is equal to the area of triangle ACD.

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Chapter 15: Area Theorems [Proof and Use] - Exercise 15 [Page 222]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 15 Area Theorems [Proof and Use]
Exercise 15 | Q 1. (e) | Page 222
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