मराठी

In the given figure, D is mid-point of side BC, the area of triangle BEA is equal to area of triangle:

Advertisements
Advertisements

प्रश्न

In the given figure, D is mid-point of side BC, the area of triangle BEA is equal to area of triangle:

पर्याय

  • BED

  • CED

  • CEA

  • ACD

MCQ
Advertisements

उत्तर

ACD

Explanation:

  • Since D is the mid-point of side BC, the line segment AD is a median of ΔABC. A median divides a triangle into two triangles of equal area, meaning:
    area of ΔABD = area of ΔACD
  • Similarly, in ΔEBC, D is the mid-point of BC, so ED is a median, which means:
    area of ΔEBD = area of ΔECD
  • Subtracting the area of ΔEBD from the area of ΔABD:
    area of ΔBEA = area of ΔABD − area of ΔEBD
  • Substituting ΔECD$ in place of ΔEBD (since their areas are equal):
    area of ΔBEA = area of ΔABD − area of ΔECD = area of ΔACD

Thus, the area of triangle BEA is equal to the area of triangle ACD.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Area Theorems [Proof and Use] - Exercise 15 [पृष्ठ २२२]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 15 Area Theorems [Proof and Use]
Exercise 15 | Q 1. (e) | पृष्ठ २२२
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×