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In the given figure, AOC is a diameter and AC is parallel to ED. If ∠CBE = 64°, calculate ∠DEC.

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Question

In the given figure, AOC is a diameter and AC is parallel to ED. If ∠CBE = 64°, calculate ∠DEC.

Sum
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Solution


Join AB,

∠ABC = 90°

(Angle in a semi circle)

∴ ∠ABE = 90° – 64° = 26°

Now, ∠ABE = ∠ACE = 26°

(Angle in the same segment)

Also, AC || ED

∴ ∠DEC = ∠ACE = 26°

(Alternate angles)

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Chapter 17: Circles - Exercise 17 (A) [Page 261]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 17 Circles
Exercise 17 (A) | Q 46. | Page 261
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