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प्रश्न
In the given figure, AOC is a diameter and AC is parallel to ED. If ∠CBE = 64°, calculate ∠DEC.

योग
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उत्तर

Join AB,
∠ABC = 90°
(Angle in a semi circle)
∴ ∠ABE = 90° – 64° = 26°
Now, ∠ABE = ∠ACE = 26°
(Angle in the same segment)
Also, AC || ED
∴ ∠DEC = ∠ACE = 26°
(Alternate angles)
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