English

In the Given Figure, Abcd is a Trapezium. P and Q Are the Midpoints of Non-parallel Side Ad and Bc Respectively. Find: Ab, If Dc = 8 Cm and Pq = 9.5 Cm - Mathematics

Advertisements
Advertisements

Question

In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: AB, if DC = 8 cm and PQ = 9.5 cm

Sum
Advertisements

Solution

Let us draw a diagonal AC which meets PQ at O as shown below:


Given DC = 8 cm and PQ = 9.5 cm
In ΔADC,

OP = `(1)/(2)"DC"`     ....(Mid-point Theorem)

⇒ OP = `(1)/(2) xx 8` = 4 cm

Now, 
OQ = PQ - OP
⇒ OQ = 9.5 - 4
= 5.5 cm

In ΔABC,

OQ = `(1)/(2)"AB"`    ....(Mid-point Theorem)

⇒ AB = 2 x OQ
= 2 x 5.5
= 11 cm.

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Mid-point and Intercept Theorems - Exercise 15.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 15 Mid-point and Intercept Theorems
Exercise 15.1 | Q 15.2

RELATED QUESTIONS

In a ∆ABC, D, E and F are, respectively, the mid-points of BC, CA and AB. If the lengths of side AB, BC and CA are 7 cm, 8 cm and 9 cm, respectively, find the perimeter of ∆DEF.


ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively
intersecting at P, Q and R. Prove that the perimeter of ΔPQR is double the perimeter of
ΔABC


BM and CN are perpendiculars to a line passing through the vertex A of a triangle ABC. If
L is the mid-point of BC, prove that LM = LN.


In ∆ABC, E is the mid-point of the median AD, and BE produced meets side AC at point Q.

Show that BE: EQ = 3: 1.


In triangle ABC, angle B is obtuse. D and E are mid-points of sides AB and BC respectively and F is a point on side AC such that EF is parallel to AB. Show that BEFD is a parallelogram.


In ΔABC, D, E, F are the midpoints of BC, CA and AB respectively. Find FE, if BC = 14 cm


D, E and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC. Prove that ΔDEF is also isosceles.


If L and M are the mid-points of AB, and DC respectively of parallelogram ABCD. Prove that segment DL and BM trisect diagonal AC.


In parallelogram ABCD, P is the mid-point of DC. Q is a point on AC such that CQ = `(1)/(4)"AC"`. PQ produced meets BC at R. Prove that

(i) R is the mid-point of BC, and

(ii) PR = `(1)/(2)"DB"`.


In ΔABC, D and E are the midpoints of the sides AB and AC respectively. F is any point on the side BC. If DE intersects AF at P show that DP = PE.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×