Question

In the given figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn. Find the area of the shaded region. [Use π = 3.14.]

Answer 1

Area of the square ABCD =(Side)²

= 4² 

= 16 cm² 

Area of the circle = πr² 

Radius = 1 cm

Area = 3.14 × (1)² 

= 3.14 cm²

Area of the quadrant of one circle`=1/4pi"r"^2` 

`=1/4xx3.14xx1^2`

= 0.785 cm² 

Area of the quadrants of four circles = 0.785 × 4 = 3.14 cm² 

Area of the shaded region = Area of the square - Area of the circle - Area of the quadrants of four circles = 16-3.14-3.14 = 9.72 cm²