Question

In the given figure, ABCD is a quadrilateral in which diagonal BD = 24 cm, AL ⊥ BD  and CM ⊥ BD such that AL = 9 cm and CM = 12 cm. Calculate the area of the quadrilateral.  

 

Answer 1

 

We have, 

BD=24 cm AL=9 cm CM=12 cm AL⊥ BD and CM ⊥BD

Area of the quadrilateral = ar (Δ ABD)+ar (Δ BCD) 

= `1/2xx BDxxAL+1/2 xxBDxxCM` 

=`1/2xx24xx9+1/2xx24xx12` 

=`108+144` 

=`252 cm^2` 

So, the area of the quadrilateral ABCD is 252`cm^2`