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Question
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AE.
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Solution
From the right triangle ADE we have
sin 60° = `"AD"/"AE"`
`sqrt(3)/(2) = (2)/"AE"`
AE = `(4)/sqrt(3)`.
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