Advertisements
Advertisements
प्रश्न
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AE.
Advertisements
उत्तर
From the right triangle ADE we have
sin 60° = `"AD"/"AE"`
`sqrt(3)/(2) = (2)/"AE"`
AE = `(4)/sqrt(3)`.
APPEARS IN
संबंधित प्रश्न
Find angle 'A' if :
Find angle 'A' if:
Find AD, if :
In trapezium ABCD, as shown, AB // DC, AD = DC = BC = 20 cm and ∠ A = 60°. Find: length of AB
In trapezium ABCD, as shown, AB // DC, AD = DC = BC = 20 cm and A = 60°. Find: distance between AB and DC.
Use the information given to find the length of AB.
Find: AD
In right-angled triangle ABC; ∠ B = 90°. Find the magnitude of angle A, if: AB is √3 times of BC.
Find AB and BC, if:
If tan x° = `(5)/(12)`,
tan y° = `(3)/(4)` and AB = 48 m; find the length of CD.
