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प्रश्न
In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.
Given that ∠AED = 60° and ∠ACD = 45°. Calculate: AC
बेरीज
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उत्तर
Again
sin 45° = `"AD"/"AC"`
`(1)/sqrt(2) = (2)/"AC"`
AC = `2sqrt(2)`.
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Solution of Right Triangles
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