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Question
In the general formula for the potential due to a dipole, setting θ = 0° and θ = 90° respectively recovers which two special cases?
Options
The equatorial case and the axial case
The axial case and the equatorial case (V = 0)
Both settings give V = 0
Both settings give the axial case
MCQ
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Solution
Setting θ = 0° gives cos θ = 1, so V = p/(4πε₀r²), the axial-point result. Setting θ = 90° gives cos θ = 0, so V = 0, the equatorial-point result. The general formula thus contains both special cases.
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