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In the general formula for the potential due to a dipole, setting θ = 0° and θ = 90° respectively recovers which two special cases?

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Question

In the general formula for the potential due to a dipole, setting θ = 0° and θ = 90° respectively recovers which two special cases?

Options

  • The equatorial case and the axial case

  • The axial case and the equatorial case (V = 0)

  • Both settings give V = 0

  • Both settings give the axial case

MCQ
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Solution

Setting θ = 0° gives cos θ = 1, so V = p/(4πε₀r²), the axial-point result. Setting θ = 90° gives cos θ = 0, so V = 0, the equatorial-point result. The general formula thus contains both special cases.

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