Advertisements
Advertisements
Question
In the following figure,
- ∠TPQ = ∠ _____ + ∠ _____.
- ∠UQR = ∠ _____ + ∠ _____.
- ∠PRS = ∠ _____ + ∠ _____.

Advertisements
Solution
In the following figure,
- ∠TPQ = ∠PQR + ∠PRQ.
- ∠UQR = ∠QRP + ∠QPR.
- ∠PRS = ∠RPQ + ∠RQP.
Explanation:

i. PQR, PRQ: ∠TPQ = ∠PQR + ∠PRQ ...[Exterior angle property]
ii. QPR, QRP: ∠UQR = ∠QPR + ∠QRP ...[Exterior angle property]
iii. RPQ, RQP: ∠PRS = ∠RPQ + ∠RQP ...[Exterior angle property]
APPEARS IN
RELATED QUESTIONS
An exterior angle of a triangle is 70° and two interior opposite angles are equal. Then measure of each of these angle will be
In the figure find the value of x
From the given figure find the value of y
In the following figure, PQ = PR, RS = RQ and ST || QR. If the exterior angle RPU is 140°, then the measure of angle TSR is ______.

In ∆ABC, ∠Α = 50°, ∠B = 70° and bisector of ∠C meets AB in D (see figure). Measure of ∠ADC is ______.

The sum of an exterior angle of a triangle and its adjacent angle is always ______.
Find the measure of ∠A in the following figure.

In ∆ABC, if ∠A = ∠C, and exterior angle ABX = 140°, then find the angles of the triangle.
In the following figure, ∆PQR is right-angled at P. U and T are the points on line QRF. If QP || ST and US || RP, find ∠S.

In the following figure, if RP = RQ, find the value of x.

