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In the figure, the optical fibre is l = 2 m long and has a diameter of d = 20 µm. If a ray of light is incident on one end of the fibre at angle θ1 = 40°

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Question

In the figure, the optical fibre is l = 2 m long and has a diameter of d = 20 µm. If a ray of light is incident on one end of the fibre at angle θ1 = 40°, the number of reflections it makes before emerging from the other end is close to:

(Refractive index of fibre is 1.31 and sin 40° = 0.64)

Options

  • 55000

  • 66000

  • 45000

  • 57000

MCQ
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Solution

57000

Explanation:

Given:

Optical fibre length, l = 2 m

Diameter of the fibre, d = 20 µm

Angle of incidence at the fiber’s entrance θ1 = 40°

Refractive index of fibre, μ2 = 1.31

To find:

The total number of reflections inside the fibre.

Calculation:

Using Snell’s law:

`mu_1/mu_2 = (sintheta_2)/(sin40^circ)`,   ...(The refractive index of air is µ1.)

`sintheta_2 = 1/1.31 sin40^circ`

θ2 = 29.39

θ = 90 − θ2

= 90 − 29.39

= 60.6  ...(θ as shown in the diagram)

tan θ = tan 60.6 = `x/d`  ....(x is labelled in the diagram.)

x = (20 × 10−6) tan 60.6 = 35.5 µm

Number of total reflections;

n = `1/x`

= `(2m)/(35.5mum)`

= 56338

Therefore, the total number of reflections is approximately 56,338. Since this does not exactly match any option, we select the nearest available option, which is 57,000.

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