English

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to ______. - Mathematics

Advertisements
Advertisements

Question

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to ______.

Options

  • 30°

  • 40°

  • 50°

  • 65°

MCQ
Fill in the Blanks
Advertisements

Solution

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to 50°.

Explanation:

Since AD = BD, triangle ADB is isosceles, so ∠BAD = ∠ABD = 65°. Thus ∠ADB = 180° − 65° − 65° = 50°. Because ∠ACB and ∠ADB subtend the same arc AB in the circle, ∠ACB = 50°.

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Circles - Exercise 15C [Page 359]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 15 Circles
Exercise 15C | Q 9. | Page 359
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×