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प्रश्न
In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to ______.

विकल्प
30°
40°
50°
65°
MCQ
रिक्त स्थान भरें
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उत्तर
In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to 50°.
Explanation:
Since AD = BD, triangle ADB is isosceles, so ∠BAD = ∠ABD = 65°. Thus ∠ADB = 180° − 65° − 65° = 50°. Because ∠ACB and ∠ADB subtend the same arc AB in the circle, ∠ACB = 50°.
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