हिंदी

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to ______. - Mathematics

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प्रश्न

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to ______.

विकल्प

  • 30°

  • 40°

  • 50°

  • 65°

MCQ
रिक्त स्थान भरें
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उत्तर

In the figure given below, AD = BD and ∠BAD = 65°. ∠ACB is equal to 50°.

Explanation:

Since AD = BD, triangle ADB is isosceles, so ∠BAD = ∠ABD = 65°. Thus ∠ADB = 180° − 65° − 65° = 50°. Because ∠ACB and ∠ADB subtend the same arc AB in the circle, ∠ACB = 50°.

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अध्याय 15: Circles - Exercise 15C [पृष्ठ ३५९]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 15 Circles
Exercise 15C | Q 9. | पृष्ठ ३५९
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