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Question
In the figure, AB = EF, BC = DE, AB and FE are perpendiculars on BE. Prove that ΔABD ≅ ΔFEC
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Solution
In ΔABD and ΔFEC
AB = FE
BD = CE ...(BC = DE; CD is common)
∠B = ∠E
ΔABD ≅ ΔFEC ...(SAS criteria).
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