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In the Amperian loop derivation for a solenoid, what is the contribution of side \(ab\) (inside, along the axis) to the line integral \(\oint \vec{B} \cdot d\vec{l}\)?

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Question

In the Amperian loop derivation for a solenoid, what is the contribution of side \(ab\) (inside, along the axis) to the line integral \(\oint \vec{B} \cdot d\vec{l}\)?

Options

  • \(0\), because \(\vec{B}\) is perpendicular to \(d\vec{l}\)

  • \(Bl\), because \(\vec{B}\) is parallel to \(d\vec{l}\)

  • \(\mu_0 n I\), directly from Ampere's Law

  • \(B l / 2\), because only half the turns contribute

MCQ
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Solution

For side \(ab\) inside the solenoid along the axis, \(\vec{B}\) is parallel to \(d\vec{l}\) (\(\vec{B} \parallel d\vec{l}\)), so \(\vec{B} \cdot d\vec{l} = B \, dl\). Integrating over the length \(l\) gives a contribution of \(Bl\). This is the only side contributing to the line integral.

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