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Question
In the adjoining figure, \(\mathrm{P}(5, -3)\) and \(\mathrm{Q}(3, y)\) are the points of trisection of the line segment joining \(\mathrm{A}(7, -2)\) and \(\mathrm{B}(1, -5)\). Then, y equals:

Options
– 4
\(-\frac{5}{2}\)
2
4
MCQ
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Solution
– 4
Explanation:
Q is the second point of trisection, so it divides AB in the ratio 2 : 1:
$$x = \frac{2 \times 1 + 1 \times 7}{3} = 3$$
$$y = \frac{2 \times (-5) + 1 \times (-2)}{3} = -4$$
Hence y = – 4.
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