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Question
In the adjoining figure, if ΔAOB ~ ΔCOD, then which of the following is true?

Options
AO.OB = OC.OD
AO.CD = OC.AB
AO.AB = OC.CD
AO.OC = OB.OD
MCQ
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Solution
AO.CD = OC.AB
Explanation:
From ΔAOB ~ ΔCOD we get ∠A = ∠C and ∠B = ∠D.
In triangles AOD and COB, ∠AOD = ∠COB (vertically opposite) and ∠A = ∠C, so ΔAOD ~ ΔCOB.
Hence, corresponding sides give `(AO)/(CO) = (OD)/(OB)`; cross-multiplying gives AO.OB = OC.OD.
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