Advertisements
Advertisements
Question
In the adjoining figure, ΔADB ∼ ΔBDC. Prove that BD2 = AD × DC.
Theorem
Advertisements
Solution
Given: ΔADB ∼ ΔBDC
∴ By the corresponding side's criterion of similarity,
`("AD")/("BD") = ("BD")/("DC")`
⇒ AD × DC = BD × BD
⇒ BD2 = AD × DC
Hence proved.
shaalaa.com
Is there an error in this question or solution?
