Question

In the adjoining figure, ΔADB ∼ ΔBDC. Prove that BD² = AD × DC.

Answer 1

Given: ΔADB ∼ ΔBDC

∴ By the corresponding side's criterion of similarity,

`("AD")/("BD") = ("BD")/("DC")`

⇒ AD × DC = BD × BD

⇒ BD² = AD × DC

Hence proved.