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Question
In the adjacent diagram, if n(U) = 125, y is two times of x and z is 10 more than x, then find the value of x, y and z
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Solution
n(U) = 125
y = 2x and z = x + 10
n(U) = x + 4 + y + 17 + 3 + 6 + z + 5
125 = x + 4 + 2x + 17 + 3 + 6 + x + 10 + 5
125 = 4x + 45
125 – 45 = 4x
80 = 4x
x = `80/4` = 20
y = 2x
= 2 × 20
= 40
z = x + 10
= 20 + 10
= 30
∴ The value of x = 20, y = 40 and z = 30.
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