Advertisements
Advertisements
Question
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
Options
70°
45°
50°
60°
Advertisements
Solution
Rhombus ABCD is given as follows:

It is given that∠ACB = 40°.
Therefore, ∠OCB = 40° (Because O lies on AC)
We know that the diagonals of a rhombus intersect at right angle.
Therefore, ∠BOC = 90°
By angle sum property of a triangle, we get:
∠CBO + ∠OCB + ∠BOC = 180°
∠CBO + 40° + 90° = 180°
∠CBO+ 130° = 180 °
∠CBO = 50°
Since, O lies on BD
∠CBD = 50°
Also , CB || DA
Therefore,
∠ADB = ∠CBD
∠ADB = 50°
Hence, the correct choice is (c).
APPEARS IN
RELATED QUESTIONS

Find x + y + z
If PQRS is a square, then write the measure of ∠SRP.
If the angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13, then find the measure of the smallest angle.
The diagonals of a rectangle ABCD meet at O, If ∠BOC = 44°, find ∠OAD.
In ΔABC, ∠A = 30°, ∠B = 40° and ∠C = 110°. The angles of the triangle formed by joining the mid-points of the sides of this triangle are
Can the angles 110º, 80º, 70º and 95º be the angles of a quadrilateral? Why or why not?
Can all the angles of a quadrilateral be acute angles? Give reason for your answer.
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
The sum of all ______ of a quadrilateral is 360°.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.
