Advertisements
Advertisements
प्रश्न
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
विकल्प
70°
45°
50°
60°
Advertisements
उत्तर
Rhombus ABCD is given as follows:
It is given that∠ACB = 40°.
Therefore, ∠OCB = 40° (Because O lies on AC)
We know that the diagonals of a rhombus intersect at right angle.
Therefore, ∠BOC = 90°
By angle sum property of a triangle, we get:
∠CBO + ∠OCB + ∠BOC = 180°
∠CBO + 40° + 90° = 180°
∠CBO+ 130° = 180 °
∠CBO = 50°
Since, O lies on BD
∠CBD = 50°
Also , CB || DA
Therefore,
∠ADB = ∠CBD
∠ADB = 50°
Hence, the correct choice is (c).
APPEARS IN
संबंधित प्रश्न
Find x + y + z + w
Three angles of a quadrilateral are respectively equal to 110°, 50° and 40°. Find its fourth angle
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
If the angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13, then find the measure of the smallest angle.
In the given figure, ABCD is a rectangle in which diagonal AC is produced to E. If ∠ECD = 146°, find ∠AOB.
Diagonals necessarily bisect opposite angles in a
If the diagonals of a rhombus are 18 cm and 24 cm respectively, then its side is equal to
In ΔABC, ∠A = 30°, ∠B = 40° and ∠C = 110°. The angles of the triangle formed by joining the mid-points of the sides of this triangle are
The angles of a quadrilateral are in the ratio 1 : 2 : 3 : 4. The smallest angle is ______.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.
