Advertisements
Advertisements
प्रश्न
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
विकल्प
70°
45°
50°
60°
Advertisements
उत्तर
Rhombus ABCD is given as follows:
It is given that∠ACB = 40°.
Therefore, ∠OCB = 40° (Because O lies on AC)
We know that the diagonals of a rhombus intersect at right angle.
Therefore, ∠BOC = 90°
By angle sum property of a triangle, we get:
∠CBO + ∠OCB + ∠BOC = 180°
∠CBO + 40° + 90° = 180°
∠CBO+ 130° = 180 °
∠CBO = 50°
Since, O lies on BD
∠CBD = 50°
Also , CB || DA
Therefore,
∠ADB = ∠CBD
∠ADB = 50°
Hence, the correct choice is (c).
APPEARS IN
संबंधित प्रश्न
Find x in the following figures.
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.
The two diagonals are equal in a
The figure formed by joining the mid-points of the adjacent sides of a square is a
The diagonals AC and BD of a rectangle ABCD intersect each other at P. If ∠ABD = 50°, then ∠DPC =
One angle of a quadrilateral is of 108º and the remaining three angles are equal. Find each of the three equal angles.
In the following figure, P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. Prove that AD = 2CD.
The sum of all ______ of a quadrilateral is 360°.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.
