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In an R-l-c Parallel Circuit the Current Through the Resistor, Inductor(Pure), and Capacitor (Pure) Are 20a, 15a and 40a Respectively. What is the Current from the Supply ?Draw the Phasor Diagram. - Basic Electrical and Electronics Engineering

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Question

In an R-L-C parallel circuit the current through the resistor, inductor(pure), and capacitor (pure) are 20A, 15A and 40A respectively. What is the current from the supply ?draw the phasor diagram.

Sum
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Solution

`"I"_"R"=20"A"`        `"I"_"L"=15"A"`      `"I"_"C"=40"A"`

IS be the source current.

`"I"_"S"^2="I"_"R"^2+("I"_"L"-"I"_"C")^2`

`"I"_"S"=sqrt("I"_"R"^2+("I"_"L"-"I"_"C")^2)`

`"I"_"S"=sqrt(20^2+(15-40)^2)=sqrt(20^2+(-25)^2`

IS= ๐Ÿ‘๐Ÿ. ๐ŸŽ๐Ÿ๐Ÿ“ A

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R-L, R-C and R-LC parallel circuits
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2018-2019 (December) CBCGS
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