Question

In an R-L-C parallel circuit the current through the resistor, inductor(pure), and capacitor (pure) are 20A, 15A and 40A respectively. What is the current from the supply ?draw the phasor diagram.

Answer 1

`"I"_"R"=20"A"`        `"I"_"L"=15"A"`      `"I"_"C"=40"A"`

I_S be the source current.

`"I"_"S"^2="I"_"R"^2+("I"_"L"-"I"_"C")^2`

`"I"_"S"=sqrt("I"_"R"^2+("I"_"L"-"I"_"C")^2)`

`"I"_"S"=sqrt(20^2+(15-40)^2)=sqrt(20^2+(-25)^2`

I_S= 𝟑𝟐. 𝟎𝟏𝟓 A