Advertisements
Advertisements
Question
In the given figure, ΔPQR is an isosceles triangle with PQ = PR and m ∠PQR = 35°. Find m ∠QSR and m ∠QTR.

Advertisements
Solution
Disclaimer: Figure given in the book was showing m∠PQR as m∠SQR. It is given that ΔPQR is an isosceles triangle with PQ = PR and m∠PQR = 35°
We have to find the m∠QSR and m∠QTR
Since ΔPQR is an isosceles triangle
So ∠PQR = ∠PRQ = 35°
Then
`angle QPR = 180° - (anglePQR + anglePRQ)`
= 180° - (35° + 35°)
=180° - 70°
=110°
Since PQTR is a cyclic quadrilateral
So
`angleP + angleT = 180°`
`angle T = 180° - 110°`
= 70°
In cyclic quadrilateral QSRT we have
`angle S + angle T` = 180°
`angle S = 180° - 70°`
= 110°
Hence,
`m angleQSR `= 110° and `angleQTR` = 70°
APPEARS IN
RELATED QUESTIONS
If AB, AC, PQ are tangents in Fig. and AB = 5 cm find the perimeter of ΔAPQ.
In the given figure, PA and PB are tangents to the circle from an external point P. CD is another tangent touching the circle at Q. If PA = 12 cm, QC = QD = 3 cm, then find PC + PD.

AB and CD are two equal chords of a drde intersecting at Pas shown in fig. P is joined to O , the centre of the cirde. Prove that OP bisects ∠ CPB.

Use the figure given below to fill in the blank:
Diameter of a circle is ______.

State, if the following statement is true or false:
The longest chord of a circle is its diameter.
Find the length of the chord AC where AB and CD are the two diameters perpendicular to each other of a circle with radius `4sqrt(2)` cm and also find ∠OAC and ∠OCA
In the following figure, ∠AOB = 90º and ∠ABC = 30º, then ∠CAO is equal to ______.

A circle of radius 3 cm can be drawn through two points A, B such that AB = 6 cm.
If two chords AB and CD of a circle AYDZBWCX intersect at right angles (see figure), prove that arc CXA + arc DZB = arc AYD + arc BWC = semi-circle.

Which statement correctly defines a chord?
