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Question
In fig., line BC || line DE, AB = 2, BD = 3, AC = 4 and CE = x, then find the value of x.

Sum
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Solution
In ΔADE, line BC || seg DE ...[Given]
∴ `(AB)/(BD) = (AC)/(CE"` ...[Basic proportionality theorem]
∴ `2/3 = 4/x` ...[Given]
∴ 2 × x = 4 × 3
∴ 2x = 12
∴ x = `12/2`
∴ x = 6
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