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Question
In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.
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Solution
Given that in the figure AB =CD and . AD=BC
We have to prove
ΔADC≅ΔCBA
Now,
Consider ΔADC and ΔCBA
We have
AB = CD [Given]
BC = AD [Given]
And AC=AC [Common side]
So, by SSS congruence criterion, we have
ΔADC≅ΔCBA
∴ Hence proved
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