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In each of the given figures; PA = PB and QA = QB. i. ii. Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB.

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Question

In each of the given figures; PA = PB and QA = QB. 

i.
ii.

Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB. Hence, state the locus of the points equidistant from two given fixed points.

Sum
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Solution

Construction: Join PQ which meets AB in D. 

 

Proof: P is equidistant from A and B.

∴ P lies on the perpendicular bisector of AB.

Similarly, Q is equidistant from A and B.

∴ Q lies on perpendicular bisector of AB.

∴ P and Q both lie on the perpendicular bisector of AB.

∴ PQ is perpendicular bisector of AB.

Hence, locus of the points which are equidistant from two fixed points, is a perpendicular bisector of the line joining the fixed points. 

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Chapter 16: Loci (Locus and Its Constructions) - Exercise 16 (A) [Page 237]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 16 Loci (Locus and Its Constructions)
Exercise 16 (A) | Q 5. | Page 237

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