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Question
In the below Fig, ABCD and PQRC are rectangles and Q is the mid-point of Prove thaT
i) DP = PC (ii) PR = `1/2` AC
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Solution
(i)In DADC, Q is the midpoint of AC such that
PQ || AD
∴ P is the midpoint of DC
⇒ DP = DC [Using converse of midpoint theorem]
(ii)Similarly, R is the midpoint of BC
∴ PR = `1/2` BD [Diagonal of rectangle are equal \BD = AC ]
PR = `1/2` AC
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