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In an Arithmetic Progression (A.P.), the fourth and sixth terms are 8 and 14 respectively. Find the: i. first term ii. common difference iii. sum of the first 20 terms.

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Question

In an Arithmetic Progression (A.P.), the fourth and sixth terms are 8 and 14 respectively. Find the:

  1. first term 
  2. common difference 
  3. sum of the first 20 terms.
Sum
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Solution

Let a and d be the first term and common difference.

$$a + 3d = 8$$ and $$a + 5d = 14$$. 

Subtracting: $$2d = 6 \Rightarrow d = 3$$. 

Then $$a + 9 = 8 \Rightarrow a = -1$$.

$$S_{20} = \frac{20}{2}[2(-1) + 19(3)]$$

$$= 10(-2 + 57)$$

$$= 550$$

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Chapter 10: Arithmetic Progression - EXERCISE 10B [Page 167]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
EXERCISE 10B | Q 14. | Page 167
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