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In Ammonia molecule the bond angle is 107° and in water molecule it is 104°35', although in both the central atoms are sp3 hybridized Explain.

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Question

In Ammonia molecule the bond angle is 107° and in water molecule it is 104°35', although in both the central atoms are sp3 hybridized Explain.

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Solution

  1. The ammonia molecule has sp3 hybridization. The expected bond angle is 109°28′. But the actual bond angle is 107°18′. It is due to the following reasons:
    1. One lone pair and three bond pairs are present in the ammonia molecule.
    2. The strength of lone pair-bond pair repulsion is much higher than that of bond pair-bond pair repulsion.
    3. Due to these repulsions, there is a small decrease in bond angle (∼2°) from 109°28′ to 107°18′.
  2. The water molecule has sp3 hybridization. The expected bond angle is 109°28′. But the actual bond angle is 104°35′. It is due to the following reasons:
    1. Two lone pairs and two bond pairs are present in the water molecules.
    2. The decreasing order of the repulsion is Lone pair-Lone pair > Lone pair-Bond pair > Bond pair-Bond pair.
    3. Due to these repulsions, there is a small decrease in bond angle (∼5°) from 109°28′ to 104°35′.
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Chapter 5: Chemical Bonding - Exercises [Page 79]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 5 Chemical Bonding
Exercises | Q 3. (G) | Page 79

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