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प्रश्न
In Ammonia molecule the bond angle is 107° and in water molecule it is 104°35', although in both the central atoms are sp3 hybridized Explain.
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उत्तर
- The ammonia molecule has sp3 hybridization. The expected bond angle is 109°28′. But the actual bond angle is 107°18′. It is due to the following reasons:
- One lone pair and three bond pairs are present in the ammonia molecule.
- The strength of lone pair-bond pair repulsion is much higher than that of bond pair-bond pair repulsion.
- Due to these repulsions, there is a small decrease in bond angle (∼2°) from 109°28′ to 107°18′.
- The water molecule has sp3 hybridization. The expected bond angle is 109°28′. But the actual bond angle is 104°35′. It is due to the following reasons:
- Two lone pairs and two bond pairs are present in the water molecules.
- The decreasing order of the repulsion is Lone pair-Lone pair > Lone pair-Bond pair > Bond pair-Bond pair.
- Due to these repulsions, there is a small decrease in bond angle (∼5°) from 109°28′ to 104°35′.
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संबंधित प्रश्न
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| Examples | C2H6 Ethane | C2H4 Ethene | C2H2 Ethyne |
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\[\begin{array}{cc} \backslash \phantom{......}/\phantom{.}\\ \ce{—C – C —}\\ /\phantom{......}\backslash\phantom{.}\end{array}\] |
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| BeCl2 | 180° | ||
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