Question

Why is bond order of Be₂ molecule zero?

(N_b = bonding electrons, N_a = antibonding electrons)

पर्याय

• N_b > N_a

• N_b = N_a 

• `"N"_"b"/"N"_"a"` = Zero

• N_b < N_a

Answer 1

N_b = N_a 

Explanation:

In Be₂ molecule,

`sigma_(1"s"^2)  sigma_(1"s"^2)^*  sigma_(2"s"^2) sigma_(2"s"^2)^*`

N_b = 4, N_a = 4

Bond order = `("N"_"b" - "N"_"a")/2` = 0