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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

F-Be-F is a liner molecule but H-O-H is angular. Explain.

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प्रश्न

F-Be-F is a liner molecule but H-O-H is angular. Explain.

थोडक्यात उत्तर
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उत्तर

  1. In the BeF2 molecule, the central beryllium atom undergoes sp hybridization giving rise to two sp hybridized orbitals placed diagonally opposite with an angle of 180°. Thus, F-Be-F is a linear molecule.
  2. In the H2O molecule, the central oxygen atom undergoes sp3 hybridization giving rise to four sp3 hybridized orbitals directed towards four corners of a tetrahedron. There are two lone pairs of electrons in two of the sp3 hybrid orbitals of oxygen. The lone pair-lone pair repulsion distorts the structure. Hence, H-O-H is angular or V-shaped.
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पाठ 5: Chemical Bonding - Exercises [पृष्ठ ७९]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 5 Chemical Bonding
Exercises | Q 3. (K) | पृष्ठ ७९

संबंधित प्रश्‍न

Give a reason for HF is a polar molecule


Write the geometry and bond angle present in ammonia.


In the case of bond formation in Acetylene molecule: State number of sigma and pi bonds formed.


In the case of bond formation in Acetylene molecule: Name the type of Hybridization.


Define Bond Enthalpy


Define Bond Length


Predict the shape and bond angles in the following molecule:

CF4


Predict the shape and bond angles in the following molecule:

NF3


Predict the shape and bond angles in the following molecule:

HCN


Using data from the Table, answer the following:

Examples C2H6 Ethane C2H4 Ethene C2H2 Ethyne
Structure

\[\begin{array}{cc} \backslash \phantom{......}/\phantom{.}\\ \ce{—C – C —}\\  /\phantom{......}\backslash\phantom{.}\end{array}\]

\[\begin{array}{cc} \backslash \phantom{......}/\\ \ce{C \text{=} C}\\  /\phantom{......}\backslash\end{array}\]

\[\ce{- C ≡ C -}\]
Type of bond between carbons single double triple
Bond length (nm) 0.154 0.134 0.120
Bond Enthalpy kJ mol-1 348 612 837
  1. What happens to the bond length when unsaturation increases?
  2. Which is the most stable compound?
  3. Indicate the relationship between bond strength and Bond enthalpy.
  4. Comment on the overall relation between Bond length, Bond Enthalpy, and Bond strength and stability.

Complete the flow chart.

Molecular Formula Structural Formula Shape/ Geometry Bond angle
BeCl2     180°
  O=C=O Linear  
C2H2      

Write the formula to calculate the bond order of molecule.


In gas phase H-O-O-H bond angle in H2O2 is ______.


What is the value of C-O-H bond angle in CH3_OH?


What is the H-S-H bond angle in H2S?


The hybridization and bond angle in BeCl2 molecule are ____________ respectively.


Which of the following pairs have identical bond order?


The bond angle is minimum in ____________.


Identify the CORRECT option.


Why is bond order of Be2 molecule zero?

(Nb = bonding electrons, Na = antibonding electrons)


What is the bond order of Be2 molecule?


Consider the ions/molecule:

\[\ce{O^+_2, O_2, O^-_2, O^{2-}_2}\]

For increasing bond order the correct option is:


What is the bona order of O2 molecules?


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