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Question
In ΔABC, AB = AC and ∠A : ∠B = 4 : 3. Find the measure of ∠C.
Sum
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Solution
We are given:
AB = AC triangle is isosceles ⇒ ∠B = ∠C
∠A : ∠B = 4 : 3
∠A = 4x
∠B = ∠C = 3x ...(Since AB = AC, the base angles are equal)
Using the angle sum property of a triangle:
∠A + ∠B + ∠C = 180°
4x + 3x + 3x = 180°
⇒ 10x = 180°
⇒ x = 18°
Now,
∠A = 4x = 72°
∠B = ∠C = 3x = 54°
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