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In a rhombus PQRS, ∠P = (4x – 10)° and ∠R = (3x + 20)°. Find the values of x and ∠Q. - Mathematics

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Question

In a rhombus PQRS, ∠P = (4x – 10)° and ∠R = (3x + 20)°. Find the values of x and ∠Q.

Sum
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Solution

Given,

In a rhombus PQRS, ∠P = (4x – 10)° and ∠R = (3x + 20)°.


The opposite angles of a rhombus are equal and the opposite sides are also equal,

⇒ ∠P = ∠R

⇒ 4x – 10 = 3x + 20

⇒ 4x – 3x = 20 + 10

⇒ x = 30°

The sum of the adjacent sides of a parallelogram is linear,

⇒ ∠P + ∠Q = 180°

⇒ 4x – 10° + ∠Q = 180°

⇒ ∠Q = 180° + 10° – 120°

⇒ ∠Q = 190° – 120° = 70°

Hence, this is required.

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Chapter 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - EXERCISE 12A [Page 139]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 12 Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons)
EXERCISE 12A | Q 10. | Page 139
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