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प्रश्न
In a rhombus PQRS, ∠P = (4x – 10)° and ∠R = (3x + 20)°. Find the values of x and ∠Q.
योग
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उत्तर
Given,
In a rhombus PQRS, ∠P = (4x – 10)° and ∠R = (3x + 20)°.

The opposite angles of a rhombus are equal and the opposite sides are also equal,
⇒ ∠P = ∠R
⇒ 4x – 10 = 3x + 20
⇒ 4x – 3x = 20 + 10
⇒ x = 30°
The sum of the adjacent sides of a parallelogram is linear,
⇒ ∠P + ∠Q = 180°
⇒ 4x – 10° + ∠Q = 180°
⇒ ∠Q = 180° + 10° – 120°
⇒ ∠Q = 190° – 120° = 70°
Hence, this is required.
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