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If \[y=[u(x)]^{v(x)}\], which expression gives \[\frac{dy}{dx}\] in logarithmic differentiation?

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Question

If \[y=[u(x)]^{v(x)}\], which expression gives \[\frac{dy}{dx}\] in logarithmic differentiation?

Options

  • \[\frac{dy}{dx}=\frac{1}{y}\left[\frac{v(x)}{u(x)}u'(x)+v'(x)\log[u(x)]\right]\]

  • \[\frac{dy}{dx}=y\left[\frac{v(x)}{u(x)}u'(x)+v'(x)\log[u(x)]\right]\]

  • \[\frac{dy}{dx}=y\left[\frac{u(x)}{v(x)}v'(x)+u'(x)\log[v(x)]\right]\]

  • \[\frac{dy}{dx}=y\left[\frac{v(x)}{u(x)}v'(x)+u'(x)\log[u(x)]\right]\]

MCQ
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Solution

For \[y=[u(x)]^{v(x)}\], the derivative contains the factor \[y\]. The first term is \[\frac{v(x)}{u(x)}u'(x)\], and the second is \[v'(x)\log[u(x)]\].

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