Advertisements
Advertisements
Question
If x = 3, y = 2 and z = 1; find the value of y2 – x2 + 6z2
Sum
Advertisements
Solution
x = 3, y = 2, z = 1
y2 – x2 + 6z2
= (2)2 − (3)2 + 6(1)2
= 4 – 9 + 6 × 1
= 4 – 9 + 6
= 10 – 9
= 1
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + 2b2 − 3c2
If a = 3, b = 0, c = 2 and d = 1, find the value of a2 + b2 − c2 + d2
If x = 2, y = 5 and z = 4, find the value of the following:
`(5"x"^4"y"^2"z"^2)/(2"x"^2)`
Evaluate:
6m – (4m – m)
Simplify:
(a + b) − (c + d) − (e − f)
Simplify:
3x − [5y − {6y + 2 (10y − x)}]
Fill in the blank:
6p − 5x + q = 6p − (...........)
If x = 3, y = 2 and z = 1; find the value of xy
Multiply and then evaluate:
(x – 2y + z) and (x – 3z); when x = − 2, y = − 1 and z = 1.
In the context of algebra, what is the primary definition of 'substitution'?
