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Question
If x - 2 and `x - 1/2` both are the factors of the polynomial nx2 − 5x + m, then show that m = n = 2
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Solution
Let p(x) = nx2 − 5x + m.
It given that (x − 2) and `(x - 1/2) `are the factors of the polynomial p(x) = nx2 − 5x + m.
∴ By factor theorem, p(2) = 0 and `p(1/2) = 0`.
p(2) = 0
⇒ n ×(2)2 − 5 × 2 + m = 0
⇒ 4n − 10 + m = 0
⇒ 4n + m = 10 ...(1)
Also,
`p(1/2) = 0`
⇒ `n(1/2)^2 - 5 xx 1/2 + m = 0`
⇒ `n/4 + m = 5/2`
⇒ n + 4m = 10 ...(2)
From (1) and (2), we have
4n + m = n + 4m
⇒ 4n − n = 4m − m
⇒ 3n = 3m
⇒ n = m
Putting n = m in (1), we have
4m + m = 10
⇒ 5m = 10
⇒ m = 2
∴ n = m = 2
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