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If the ratio of the sums of first n terms of two A.P.s is (5n + 13)/(7n + 27), then the ratio of their 4^th terms is ______.

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Question

If the ratio of the sums of first n terms of two A.P.s is `(5n + 13)/(7n + 27)`, then the ratio of their 4th terms is ______.

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Solution

If the ratio of the sums of first n terms of two A.P.s is `(5n + 13)/(7n + 27)`, then the ratio of their 4th terms is 12 : 19.

Explanation:

For an A.P., `S_n = n/2 [2a + (n - 1)d]` 

So `(S_(n1))/(S_(n2)) = [2a_1 + (n - 1)d_1]/[2a_2 + (n - 1)d_2]` 

= `(5n + 13)/(7n + 27)` 

To get the ratio of the m-th terms a + (m – 1)d, replace `(n - 1)/2` by (m – 1), i.e. take n = 2m – 1.

For m = 4, n = 7, so the ratio of 4th terms is (5 × 7 + 13) : (7 × 7 + 27) = 48 : 76 = 12 : 19.

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Chapter 5: Arithmetic Progressions - FILL IN THE BLANK TYPE QUESTIONS (FBQs) [Page 5.46]

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R.D. Sharma Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
FILL IN THE BLANK TYPE QUESTIONS (FBQs) | Q 20. | Page 5.46
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