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Question
If Sn = n (4n + 1) is the sum of n terms of an A.P., then its common difference is ______.
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Solution
If Sn = n (4n + 1) is the sum of n terms of an A.P., then its common difference is 8.
Explanation:
Let Sn = 4n2 + n be the sum of n terms.
The nth term Tn = Sn – Sn – 1
= [4n2 + n] – [4(n – 1)2 + (n – 1)]
= 8n – 3
So Tn = a + (n – 1)d
= 5 + (n – 1) × 8
Hence the common difference d = 8.
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