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If the numerator of a fraction is multiplied by 2 and the denominator is reduced by 5 the fraction becomes 6/5. And, if the denominator is doubled and the numerator is increased by 8

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Question

If the numerator of a fraction is multiplied by 2 and the denominator is reduced by 5 the fraction becomes `6/5`. And, if the denominator is doubled and the numerator is increased by 8, the fraction becomes `2/5`. Find the fraction.

Sum
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Solution

Given: Let the fraction be `x/y`.

From "numerator × 2, denominator –5 gives `6/5`":

`(2x)/(y - 5) = 6/5` 

⇒ 10x = 6(y – 5) 

⇒ 10x = 6y – 30

⇒ 5x – 3y = –15

From "numerator +8, denominator × 2 gives `2/5`":

`(x + 8)/(2y) = 2/5`

⇒ 5(x + 8) = 4y 

⇒ 5x + 40 = 4y

⇒ 5x – 4y = –40

Subtract the second equation from the first:

(5x – 3y) – (5x – 4y)

= –15 – (–40) 

⇒ y = 25

Substitute y = 25 into 5x – 3y = –15: 

5x – 75 = –15 

⇒ 5x = 60

⇒ x = 12

The fraction is `12/25`.

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Chapter 3: Pair of Linear Equations in Two Variables - EXERCISE 3.8 [Page 3.57]

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R.D. Sharma Mathematics [English] Class 10
Chapter 3 Pair of Linear Equations in Two Variables
EXERCISE 3.8 | Q 8. | Page 3.57
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